View Single Post
Old 04-05-2018, 07:54 AM   #27
Senior Member
250ptm's Avatar
Join Date: Feb 2010
Location: Tasmania
Posts: 238
Subframe: Other
CC: 1600
Make: Honda
ECU: odb1

Instant Custard/Gadget555
Heres some info that may explain it.
I know my car is 839 Kg (Driver + full Fuel) and can achieve a 7.21Ms^2 deceleration rate as tested on a brake dyno 3 months ago.
So I borrowed this equation from Wiki: I use a different one but the result is very similar.
a = deceleration rate m/s^2 (7.21Ms^2)
G = Gravity (9.81 m/s^2)
h= center of gravity above ground level (0.5 M)
W= Weight of Car. (839 kg)
B = Wheelbase (2.03 M)
Weight f = The change of weight over the front axles during braking at 7.21
= a/G * (h/B)* W
So I will use my numbers as an example.
Wf = (7.21/9.81) * (0.5/2.03)* 839
Wf = (0.7349) * (0.2463)*839
Wf = 0.7349 * (206.6)
Wf= 153 KG Increase in weight over the front wheels while braking at my maximum decal rate.
This means a decrease of theweight over the rear tires.
It only took me 3 years to reach 100 posts and become a senior member!

Last edited by 250ptm; 04-05-2018 at 09:15 AM.
250ptm is offline   Reply With Quote